Optimal. Leaf size=206 \[ -\frac {128 i \sqrt {a+i a \tan (c+d x)}}{585 a^3 d (e \sec (c+d x))^{3/2}}+\frac {256 i \sqrt {e \sec (c+d x)}}{585 a^2 d e^2 \sqrt {a+i a \tan (c+d x)}}+\frac {32 i}{195 a^2 d \sqrt {a+i a \tan (c+d x)} (e \sec (c+d x))^{3/2}}+\frac {16 i}{117 a d (a+i a \tan (c+d x))^{3/2} (e \sec (c+d x))^{3/2}}+\frac {2 i}{13 d (a+i a \tan (c+d x))^{5/2} (e \sec (c+d x))^{3/2}} \]
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Rubi [A] time = 0.40, antiderivative size = 206, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 3, integrand size = 30, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.100, Rules used = {3502, 3497, 3488} \[ \frac {256 i \sqrt {e \sec (c+d x)}}{585 a^2 d e^2 \sqrt {a+i a \tan (c+d x)}}-\frac {128 i \sqrt {a+i a \tan (c+d x)}}{585 a^3 d (e \sec (c+d x))^{3/2}}+\frac {32 i}{195 a^2 d \sqrt {a+i a \tan (c+d x)} (e \sec (c+d x))^{3/2}}+\frac {16 i}{117 a d (a+i a \tan (c+d x))^{3/2} (e \sec (c+d x))^{3/2}}+\frac {2 i}{13 d (a+i a \tan (c+d x))^{5/2} (e \sec (c+d x))^{3/2}} \]
Antiderivative was successfully verified.
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Rule 3488
Rule 3497
Rule 3502
Rubi steps
\begin {align*} \int \frac {1}{(e \sec (c+d x))^{3/2} (a+i a \tan (c+d x))^{5/2}} \, dx &=\frac {2 i}{13 d (e \sec (c+d x))^{3/2} (a+i a \tan (c+d x))^{5/2}}+\frac {8 \int \frac {1}{(e \sec (c+d x))^{3/2} (a+i a \tan (c+d x))^{3/2}} \, dx}{13 a}\\ &=\frac {2 i}{13 d (e \sec (c+d x))^{3/2} (a+i a \tan (c+d x))^{5/2}}+\frac {16 i}{117 a d (e \sec (c+d x))^{3/2} (a+i a \tan (c+d x))^{3/2}}+\frac {16 \int \frac {1}{(e \sec (c+d x))^{3/2} \sqrt {a+i a \tan (c+d x)}} \, dx}{39 a^2}\\ &=\frac {2 i}{13 d (e \sec (c+d x))^{3/2} (a+i a \tan (c+d x))^{5/2}}+\frac {16 i}{117 a d (e \sec (c+d x))^{3/2} (a+i a \tan (c+d x))^{3/2}}+\frac {32 i}{195 a^2 d (e \sec (c+d x))^{3/2} \sqrt {a+i a \tan (c+d x)}}+\frac {64 \int \frac {\sqrt {a+i a \tan (c+d x)}}{(e \sec (c+d x))^{3/2}} \, dx}{195 a^3}\\ &=\frac {2 i}{13 d (e \sec (c+d x))^{3/2} (a+i a \tan (c+d x))^{5/2}}+\frac {16 i}{117 a d (e \sec (c+d x))^{3/2} (a+i a \tan (c+d x))^{3/2}}+\frac {32 i}{195 a^2 d (e \sec (c+d x))^{3/2} \sqrt {a+i a \tan (c+d x)}}-\frac {128 i \sqrt {a+i a \tan (c+d x)}}{585 a^3 d (e \sec (c+d x))^{3/2}}+\frac {128 \int \frac {\sqrt {e \sec (c+d x)}}{\sqrt {a+i a \tan (c+d x)}} \, dx}{585 a^2 e^2}\\ &=\frac {2 i}{13 d (e \sec (c+d x))^{3/2} (a+i a \tan (c+d x))^{5/2}}+\frac {16 i}{117 a d (e \sec (c+d x))^{3/2} (a+i a \tan (c+d x))^{3/2}}+\frac {32 i}{195 a^2 d (e \sec (c+d x))^{3/2} \sqrt {a+i a \tan (c+d x)}}+\frac {256 i \sqrt {e \sec (c+d x)}}{585 a^2 d e^2 \sqrt {a+i a \tan (c+d x)}}-\frac {128 i \sqrt {a+i a \tan (c+d x)}}{585 a^3 d (e \sec (c+d x))^{3/2}}\\ \end {align*}
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Mathematica [A] time = 0.59, size = 107, normalized size = 0.52 \[ \frac {\sec ^4(c+d x) (1040 \sin (2 (c+d x))-120 \sin (4 (c+d x))-1300 i \cos (2 (c+d x))+75 i \cos (4 (c+d x))-351 i)}{2340 a^2 d (\tan (c+d x)-i)^2 \sqrt {a+i a \tan (c+d x)} (e \sec (c+d x))^{3/2}} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.83, size = 111, normalized size = 0.54 \[ \frac {\sqrt {\frac {a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}} \sqrt {\frac {e}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}} {\left (-195 i \, e^{\left (10 i \, d x + 10 i \, c\right )} + 2145 i \, e^{\left (8 i \, d x + 8 i \, c\right )} + 3042 i \, e^{\left (6 i \, d x + 6 i \, c\right )} + 962 i \, e^{\left (4 i \, d x + 4 i \, c\right )} + 305 i \, e^{\left (2 i \, d x + 2 i \, c\right )} + 45 i\right )} e^{\left (-\frac {13}{2} i \, d x - \frac {13}{2} i \, c\right )}}{4680 \, a^{3} d e^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{\left (e \sec \left (d x + c\right )\right )^{\frac {3}{2}} {\left (i \, a \tan \left (d x + c\right ) + a\right )}^{\frac {5}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 1.18, size = 159, normalized size = 0.77 \[ \frac {2 \left (\frac {e}{\cos \left (d x +c \right )}\right )^{\frac {3}{2}} \sqrt {\frac {a \left (i \sin \left (d x +c \right )+\cos \left (d x +c \right )\right )}{\cos \left (d x +c \right )}}\, \left (\cos ^{2}\left (d x +c \right )\right ) \left (180 i \left (\cos ^{7}\left (d x +c \right )\right )+180 \sin \left (d x +c \right ) \left (\cos ^{6}\left (d x +c \right )\right )-55 i \left (\cos ^{5}\left (d x +c \right )\right )+35 \sin \left (d x +c \right ) \left (\cos ^{4}\left (d x +c \right )\right )+8 i \left (\cos ^{3}\left (d x +c \right )\right )+48 \left (\cos ^{2}\left (d x +c \right )\right ) \sin \left (d x +c \right )+64 i \cos \left (d x +c \right )+128 \sin \left (d x +c \right )\right )}{585 d \,e^{3} a^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.97, size = 226, normalized size = 1.10 \[ \frac {45 i \, \cos \left (\frac {13}{2} \, d x + \frac {13}{2} \, c\right ) + 260 i \, \cos \left (\frac {9}{13} \, \arctan \left (\sin \left (\frac {13}{2} \, d x + \frac {13}{2} \, c\right ), \cos \left (\frac {13}{2} \, d x + \frac {13}{2} \, c\right )\right )\right ) + 702 i \, \cos \left (\frac {5}{13} \, \arctan \left (\sin \left (\frac {13}{2} \, d x + \frac {13}{2} \, c\right ), \cos \left (\frac {13}{2} \, d x + \frac {13}{2} \, c\right )\right )\right ) - 195 i \, \cos \left (\frac {3}{13} \, \arctan \left (\sin \left (\frac {13}{2} \, d x + \frac {13}{2} \, c\right ), \cos \left (\frac {13}{2} \, d x + \frac {13}{2} \, c\right )\right )\right ) + 2340 i \, \cos \left (\frac {1}{13} \, \arctan \left (\sin \left (\frac {13}{2} \, d x + \frac {13}{2} \, c\right ), \cos \left (\frac {13}{2} \, d x + \frac {13}{2} \, c\right )\right )\right ) + 45 \, \sin \left (\frac {13}{2} \, d x + \frac {13}{2} \, c\right ) + 260 \, \sin \left (\frac {9}{13} \, \arctan \left (\sin \left (\frac {13}{2} \, d x + \frac {13}{2} \, c\right ), \cos \left (\frac {13}{2} \, d x + \frac {13}{2} \, c\right )\right )\right ) + 702 \, \sin \left (\frac {5}{13} \, \arctan \left (\sin \left (\frac {13}{2} \, d x + \frac {13}{2} \, c\right ), \cos \left (\frac {13}{2} \, d x + \frac {13}{2} \, c\right )\right )\right ) + 195 \, \sin \left (\frac {3}{13} \, \arctan \left (\sin \left (\frac {13}{2} \, d x + \frac {13}{2} \, c\right ), \cos \left (\frac {13}{2} \, d x + \frac {13}{2} \, c\right )\right )\right ) + 2340 \, \sin \left (\frac {1}{13} \, \arctan \left (\sin \left (\frac {13}{2} \, d x + \frac {13}{2} \, c\right ), \cos \left (\frac {13}{2} \, d x + \frac {13}{2} \, c\right )\right )\right )}{4680 \, a^{\frac {5}{2}} d e^{\frac {3}{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 4.72, size = 135, normalized size = 0.66 \[ \frac {\sqrt {\frac {e}{\cos \left (c+d\,x\right )}}\,\left (\cos \left (2\,c+2\,d\,x\right )\,507{}\mathrm {i}+\cos \left (4\,c+4\,d\,x\right )\,260{}\mathrm {i}+\cos \left (6\,c+6\,d\,x\right )\,45{}\mathrm {i}+897\,\sin \left (2\,c+2\,d\,x\right )+260\,\sin \left (4\,c+4\,d\,x\right )+45\,\sin \left (6\,c+6\,d\,x\right )+2340{}\mathrm {i}\right )}{4680\,a^2\,d\,e^2\,\sqrt {\frac {a\,\left (\cos \left (2\,c+2\,d\,x\right )+1+\sin \left (2\,c+2\,d\,x\right )\,1{}\mathrm {i}\right )}{\cos \left (2\,c+2\,d\,x\right )+1}}} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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